Assigning Lists
- Instead of:
$foo = $bar; $baz = $quux;
- ..you could do:
($foo, $bar) = ($baz, $quux);
- Swapping can occur:
($left, $right) = ($right, $left);
| CPU: Perl, Fall 2005 | Perl, Week 2: Arrays, Hashes, Control Structures | #34 |
$foo = $bar; $baz = $quux;
($foo, $bar) = ($baz, $quux);
($left, $right) = ($right, $left);
| Copyright © 2005 Ian Langworth |